Here is the solution to URI problem ID: 1046 #include<stdio.h> #include<math.h> int main() { int s,e,duration; scanf("%d %d",&s,&e); duration=(e-s); if(duration<0) { duration=24+(e-s); printf("O JOGO DUROU %d HORA(S)\n",duration); } else if(s==e) { printf("O JOGO DUROU 24 HORA(S)\n"); } else { printf("O JOGO DUROU %d HORA(S)\n",duration); } return 0; }
Here is the solution to URI problem ID: 1044 #include<stdio.h> #include<math.h> int main() { int a,b; scanf("%d%d",&a,&b); if(a%b==0||b%a==0) {printf("Sao Multiplos\n");} else {printf("Nao sao Multiplos\n");} return 0; }
Here is the solution to URI problem ID: 1043 #include<stdio.h> #include<math.h> int main() { double A,B,C,t; scanf("%lf%lf%lf",&A,&B,&C); if(A+B>C&&B+C>A&&C+A>B) { printf("Perimetro = %.1lf\n",A+B+C); } else { t=(0.5*(A+B)*C); printf ("Area = %.1lf\n",t); } return 0; }
Here is the solution to URI problem ID: 1042 #include<stdio.h> #include<math.h> int main() { int a,b,c,d,e,f,g,h; scanf("%d %d %d",&a,&b,&c); d=(((a+b)+(abs(a-b)))/2); e=(((d+c)+(abs(d-c)))/2); if(a==e) { f=(((b+c)+(abs(b-c)))/2); if(f==b) { printf("%d\n",c); printf("%d\n",b); printf("%d\n",e); } else { ...
Here is the solution to URI problem ID: 1040 #include<stdio.h> #include<math.h> int main() { double media, N1,N2,N3,N4,s,k; scanf("%lf %lf %lf %lf",&N1,&N2,&N3,&N4); media=((N1*2/10)+(N2*3/10)+(N3*4/10)+(N4*1/10)); printf("Media: %.1lf\n",media); if(media>=7) { printf("Aluno aprovado.\n"); } else if(media>=5.0&&media<=6.9) { printf("Aluno em exame.\n"); scanf("%lf",&s); printf("Nota do exame: %.1lf\n",s); k=(media+s)/2; if(k>=5) { ...