Here is the solution to URI problem ID: 1042
#include<stdio.h>
#include<math.h>
int main()
{
int a,b,c,d,e,f,g,h;
scanf("%d %d %d",&a,&b,&c);
d=(((a+b)+(abs(a-b)))/2);
e=(((d+c)+(abs(d-c)))/2);
if(a==e)
{
f=(((b+c)+(abs(b-c)))/2);
if(f==b)
{
printf("%d\n",c);
printf("%d\n",b);
printf("%d\n",e);
}
else
{
printf("%d\n",b);
printf("%d\n",c);
printf("%d\n",e);
}
}
else if(b==e)
{
g=(((a+c)+(abs(a-c)))/2);
if(g==a)
{
printf("%d\n",c);
printf("%d\n",a);
printf("%d\n",e);
}
else
{
printf("%d\n",a);
printf("%d\n",c);
printf("%d\n",e);
}
}
else
{
h=(((a+b)+(abs(a-b)))/2);
if(h==a)
{
printf("%d\n",b);
printf("%d\n",a);
printf("%d\n",e);
}
else
{
printf("%d\n",a);
printf("%d\n",b);
printf("%d\n",e);
}
}
printf("\n%d\n%d\n%d\n",a,b,c);
return 0;
}
#include<math.h>
int main()
{
int a,b,c,d,e,f,g,h;
scanf("%d %d %d",&a,&b,&c);
d=(((a+b)+(abs(a-b)))/2);
e=(((d+c)+(abs(d-c)))/2);
if(a==e)
{
f=(((b+c)+(abs(b-c)))/2);
if(f==b)
{
printf("%d\n",c);
printf("%d\n",b);
printf("%d\n",e);
}
else
{
printf("%d\n",b);
printf("%d\n",c);
printf("%d\n",e);
}
}
else if(b==e)
{
g=(((a+c)+(abs(a-c)))/2);
if(g==a)
{
printf("%d\n",c);
printf("%d\n",a);
printf("%d\n",e);
}
else
{
printf("%d\n",a);
printf("%d\n",c);
printf("%d\n",e);
}
}
else
{
h=(((a+b)+(abs(a-b)))/2);
if(h==a)
{
printf("%d\n",b);
printf("%d\n",a);
printf("%d\n",e);
}
else
{
printf("%d\n",a);
printf("%d\n",b);
printf("%d\n",e);
}
}
printf("\n%d\n%d\n%d\n",a,b,c);
return 0;
}
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